Question

If the radius of hydrogen atom in the ground state is
0.53 Å, then the radius of Be3+ in the same state is

Answer 1

Answer:

Radius of hydrogen atom is directly proportional to principle quantum no. The first bohr orbit has degeneracy one. These orbits are called stationary orbit. It can be shown by the calculation that the radius of hydrogen atom in the ground state is 0.53 Amstrong.

Explanation:

hope this helps

Answer 2

<marquee behaviour-move><font color="orange"><h1>The radius of hydrogen atom in ground state =[(nhx2eπ)^2]/mz

If we put value of all these terms that is, n=1,h=6.026*10^-27 ,e=4.8*10^-10

m=9.1*10^-28, z=1

Radius=0.53 amstrong

Radius of hydrogen atom is directly proportional to principle quantum no.

The first bohr orbit has degeneracy one. These orbits are called stationary orbit. It can be shown by the calculation that the radius of hydrogen atom in the ground state is 0.53 Amstrong./h1></marquee>