If the radius of sphere is 10cm if it is increased by 1cm. Then find the volume of the sphere increased by?
Answers
Vol. of sphere =4/3 πr^3
r=10 cm
vol,v1= (4/3π)1000
when r is inc. by 1cm new radius =11
vol,v2=(4/3π)13331
now percent change =(v2-v1)/v1
=(331/1000) *100
=33.1%
Proved
We know that Volume of the sphere = 4/3 pi r^3
Volume of the sphere when radius = 10cm
4/3 * pi * (10)^3
Given that radius is increased by 1cm = 11cm.
Volume of the sphere when radius = 11cm
4/3 * pi * (11)^3. (New volume)
Increase in volume = 4/3 * pi * (11)^3 - 4/3 * pi * (10)^3
= 4/3 * pi * ((11)^3 - (10)^3).
= 4/3 * pi * (1331 - 1000)
= 4/3 * pi * 331
Increase % = Increase in volume/Initial volume * 100
= 4/3 * pi * 331/4/3 * pi * (10)^3 * 100
= 4/3 * 22/7 * 331 * 100
= 331/1000 * 100
= 33.1%.