Question

if the radius of sphere is double what is the ratio of volume of the first sphere that ofthe second​

Answer 1

$\huge\underline\mathrm{Solution-}$

Let the radius of sphere be "r"

Volume of sphere (V) :$\frac{4}{3} \pi {r}^{3}$

Now, when this radius is doubled

New radius of sphere = 2r

Volume of sphere (V') :$\frac{4}{3} \pi {(2r)}^{3}$

$= \frac{4}{3} \pi {8r}^{3}$

Their ratio :

$= \frac{ \frac{4}{3}\pi {r}^{3} }{ \frac{4}{3} \pi8 {r}^{3} }$

$= \frac{1}{8}$

$\huge\underline\mathrm{Answer-}$

The ratio of volume of the first sphere to the second sphere is 1 : 8

Answer 2

Answer: 1:8

Step-by-step explanation:

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