If the radius of sphere is doubled its volume become__time the volume of orginal sphere
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Answer:
Let the radius of Sphere Before= r
so the Volume of sphere before= 4/3 πr^3
After increasing
the Radius becomes = 2 × r = 2r
So,
the volume of sphere= 4/3 π (2r)^3
= 4/3 π 8r^3
So, the volume becomes 4/3 πr^3
= --------------------
4/3 π 8r^3
Now,
1/8
So, We can say that the volume becomes the 8 times of the initial one
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