Question

 If the radius of sphere is increased by 10% , by what % it's curved surface area is increased​

Answer 1

Answer:

ok

Step-by-step explanation:

r1 = r

r2 = r+(r×10/100)

for r1

surface area= 4π(r1)²

= 4×π×r²

= 4πr²

for r2

surface area= 4π(r2)²

=4π{r+r/10}²

=4π{11r/10}²

=4π{121r²/100}

now compare R1 and R2

now compare R1 and R24πr²is as 4π×121r²/100

4πr² × ((121/100)×100%)

(R1 surface area) × 121%

✓∆ there fore curved surface area increases by 121%

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