if the radius of sphere is incresed 10%, by how much % will its volume increase
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Step-by-step explanation:
Let the radius of sphere be 'r+(r/10)'
Volume of sphere=(4/3)π(r+(r/10))^3
=(4/3)(22/7)(11r/10)^3
=(4/3)(22/7)(1331r^3/1000)
Volume of a normal sphere =(4/3)π(r)^3
Comparison= {(4/3)(22/7)(1331r^3/1000)} / {(4/3)
(22/7)(r)^3}
= {(1331r^3/1000) × (1/r^3)}
= {(1331r^3/1000r^3)}
= 1.331 %
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