if the radius of the 14th Newton's ring is 2mm when the light of wavelength at 8 exponent - 4 mm is used what is the radius of the curvature of the lower surface of the lens used
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Answer:
Diameter of the 20th dark ring.
D 20
=5.8 mm=5.82×10 −3 m
Radius of the 20th dark ring
r 20
=2.91×10 −3m
Diameter of the 10th dark ring
D 10
=3.36 mm=3.36×10 −3 m
Radius of the 10th dark ring
r 10
=1.68×10 −3m
Radius of plano-convex lens (R)=1 m
Wavelength of light
= mRr n+m2 −r n2
= 10×1[(2.91×10 −3 ) 2 −(1.68×10 −3 ) 2 ]
= 10[8.4681−2.8224]×10 −6
=0.5646×10 −6
=5636 Ao .
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