If the radius of the base and the height of a right circular cone are doubled. Then find
the ratio of volumes.
Answers
Answered by
7
Step-by-step explanation:
Given:
radius of smaller cone=r
height = h1
volume of cone=V=1/3(πr^2h)----(1)
second cone(larger)
radius=2r
height=h2
volume=-2/3(πr^2h2)----(2)
1/3(πr^2h1)=2/3(πr^2h2)
h1/3=(2/3 )h2
h2/h1 =1/2
Therefore ratio of
length of the larger cone to that of the smaller cone is 1: 2
Answered by
9
Answer:
1:8
Step-by-step explanation:
let original radius & height be r & h respectively.
original volume = πr^2h/3
new Radius = 2r ,new height = 2h
new volume = π(2r)^2(2h)/3
= 8πr^2h/3
required ratio of volumes
= πr^2h/3 : 8πr^2h/3 = 1 : 8
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