Question

if the radius of the base of a right circular cone is 3rd and its height is equal to the radius of the base , then its volume is​

Answer 1

Answer:

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Radius of base of cone =3r

Height of cone = radius of base of cone =3r

Volume of cone

$\frac{1}{3} \pi {r}^{2} h = \frac{1}{3} \times (3r) ²×3r \\ \frac{1}{3} \times \pi \times 27 {r}^{3} \\ 9\pi {r}^{3}$

Therefore the volume of cone = 9πr³

Answer 2

Step-by-step explanation:

Answer:

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Radius of base of cone =3r

Height of cone = radius of base of cone =3r

• Volume of cone

$\frac{1}{3} \pi {r}^{2} h = \frac{1}{3} \times (3r) ²×3r \\ \frac{1}{3} \times \pi \times 27 {r}^{3} \\ 9\pi {r}^{3}$

Therefore the volume of cone = 9πr³