Question

if the radius of the base of a right circular cylinder is halved , keeping the height same ,find the ratio of the volume of the reduced cylinder to that of the original . please ans the question till night (2day)

Answer 1

hey friend here is your answer.

Answer 2

Answer:

The ratio of the volume of the reduced cylinder to that of the original is 1:4

Step-by-step explanation:

Let the radius of cylinder be r

Let the height be h

Volume of cylinder = $\pi r^2 h$

New radius = $\frac{r}{2}$

Height remains same

New Volume = $\pi (\frac{r}{2})^2 h$

The ratio of the volume of the reduced cylinder to that of the original :

=$\frac{\pi (\frac{r}{2})^2h}{\pi r^2 h}$.

=$\frac{1}{4}$

Hence The ratio of the volume of the reduced cylinder to that of the original is 1:4