Question

if the radius of the base of a right circular cylinder is halved keeping the height same what is the ratio of the volume of the reduced cylinder to that of the original one

Answer 1

hii mate!!

Let old radius = r1

New radius = r2 = r1/2 —(1)

Height of both (reduced and original cylinder) = h

Since volume of cylinder = πr²h

Therefore, ratio of reduced to original cylinder volume = r1²/r2² (since height is same in both and thus cancelled out)

= r1²/(r1/2)² = 4 (from equation 1)

Similarly CSA of cylinder = 2πrh

Therefore, ratio of reduced to original cylinder area= r1/r2

=r1/(r1/2) = 2

hope it helps !!☺☺☺☺☺

Answer 2

V2/V1= 1/4 that's your answer.