if the radius of the base of a right circular cylinder is halved , keeping the height same, find the ratio of the volume of the reduced cylinder to that of original cylinder.
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see attachment dear.....
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Answer is 1:4
(Pi (1/2r^2)h) /pi r^2h
=1:4
(Pi (1/2r^2)h) /pi r^2h
=1:4
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