if the radius of the base of a right circular cylinder is halved keeping the height same find the ratio of their volumes of the reduced cylinder to that of the original
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Volume of original cylinder = π(r)^2h
new r = r/2
new volume = π(r/2)^2h
=π(r)^2h/4
ratio of new volume to original volume = 1/4
= 1:4
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