Question

If the radius of the base of a right circular cylinder is halved keeping the height the same what is the ratio of the volume of the reduced cylinder to that of the original surrender

Answer 1

Ratio =

$\pi ({ \frac{r}{2} )}^{2} h \div \pi {r}^{2} h$

$\frac{ {r}^{2} }{4} \div {r}^{2}$

1:4