If the radius of the base of cylinder is halved ,keeping the height same , what will be the ratio of the volume of the reduced cylinder to that of the original
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1:4 is the right answer because 1/4/1 it becomes 1:4 at last use
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Answer:
V2 : V1 = 1 : 4
Step-by-step explanation:
VOLUME OF CYLINDER = πr²h ; where r is radius of base of cylinder ,
h is height of cylinder.
for original cylinder ; volume (V1) = πr²h
for reduced cylinder ; volume (V2) = π(r/2)²h
Ratio will be ; V2 : V1 = 1 : (2)²
= 1 : 4
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