Question

If the radius of the base of the right circular cylinder is reduced by 50%, keeping the same height, what i
ratio of the volume of the reduced cylinder to that of the original.​

Answer 1

Answer:

∴ Ratio =1:4.

Step-by-step explanation:

Let the radius of the cylinder is r and height is h

∴ Volume of the cylinder = πr

2

h

According to the question new radius is half of the initial radius

∴New radius=

2

r

Height is h.

∴New volume of the cylinder = π(

2

r

)

2

h=π

4

r

2

h

∴ The ratio of the new volume of the cylinder and initial volume of the original cylinder=

πr

2

h

π

4

r

2

h

=

4

1

∴ Ratio =1:4.