if the radius of the circular base of a frustum of acone are 33 and 27 and its slant heigjt is 10 find the height of the frustum
Answers
Answered by
9
Answer:
8
Explanation:
R = 33, r = 27 & slant height l = 10
height = √[(10^2 -(33-27)^2 ]
height = √(100 - 36) = √64 = 8
Answered by
3
Answer:
height of frustum = 8cm
Explanation:
radius of upper surface = R = 33cm
radius of lower surface = r = 27cm
slant height of frutum = l = 10cm
h^2 = {l^{2} - (R-r)^{2} ]
h^2 = {10^2 - (33-27)^2}
h^2 = {100 - 36}
h^2 = {64}
h = 8 cm
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