Question

if the radius of the cylinder is doubled and height is halved ,then show that the volume will be doubled

Answer 1

initial volume = pie × r^2 × h
new volume = 22/7 × 4r^2 × h/2
= 2(pie × r^2 × h)
= 2(initial volume) ANSWER.
THANKS...

Answer 2

hiii friend
here is your answer
assuming the initial volume be⬇⬇
$\pi \times {r}^{2} \times h$
now the final volume be⬇⬇⬇
$\pi {(2r)}^{2} \times \frac{h}{2} \\ \pi \times 4 {r}^{2} \times \frac{h}{2} \\ \pi2 {r}^{2} h \\ 2 \times (\pi {r}^{2} h)$
there the volume changes to two times..


glad to help you
hope it helps
thank you.