Question

If the radius of the earth shrinks 20% of mass remaining constant that the how much value of acceleration due to gravity change

Answer 1

r = Earth's radius - 20% of that

r = 6378000 - 6378000 × 0.2

r = 5102400 m

m = 5.972 × 10²⁴ kg

g = Gm/r²

$g = \frac{6.674 \times {10}^{ - 11} \times 5.972 \times {10}^{24} }{ {(5102400)}^{2} } \\ \\ g = \frac{39.85 \times {10}^{13} }{2.603449 \times {10}^{13} } \\ \\ g = 15.3066 \:$

Change in g = 15.3 - 9.8

Chnage in g = 5.5 m/s²