If the radius of the earth were to shrink by one percent, its mass remaining the same, the value of g on the earths surface would:a. increase by 0.5%b. increase by 2%c. decrease by 0.5%d. decrease by 2%
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F=ma=GMm/r²
on the surface of the earth
g=a=GM/r² , M is the mass of the earth, which is a constant in this case
g=GM/r²≈9.8 N/kg
g’=GM/(0.9r)²=100/81 g≈1.23g≈
So the g is increased by 0.23
Then the g is increased by 23%
on the surface of the earth
g=a=GM/r² , M is the mass of the earth, which is a constant in this case
g=GM/r²≈9.8 N/kg
g’=GM/(0.9r)²=100/81 g≈1.23g≈
So the g is increased by 0.23
Then the g is increased by 23%
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Answer:
Option (b)
Explanation:
the radius of the earth were to shrink by 1% its mass remaining the same, the acceleration due to gravity on the earth's surface would. If the radius of the earth were to shrink by one percent, mass remaining the same, the value of g will increase by 2%.
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