If the radius of the end of a bucket 24 cm height are 5cm and 15cm find the surface are of the bucket
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Since the bucket is in shape of a frustum we get,
R1=5 cm
R2=15 cm
H=24 cm
Slant height of cone=√(R1-R2)² +H²=26 cm
Total surface area=π(R1+R2)l +πR1²+πR2²=π[520+25+225]=22/7××770=2420 cm²
R1=5 cm
R2=15 cm
H=24 cm
Slant height of cone=√(R1-R2)² +H²=26 cm
Total surface area=π(R1+R2)l +πR1²+πR2²=π[520+25+225]=22/7××770=2420 cm²
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