Question

if the radius of the first orbit of hydrogen atom is 5.3 × 10 to the power minus 11 M then the radius of third orbit is​

Answer 1

Answer:

radius of first orbit = 5.3 × 10⁻¹¹ m

radius of third orbit = 5.3 × 10⁻¹¹ × n² / Z

                                = 5.3 × 10⁻¹¹ × 3²

                                = 5.3 × 10⁻¹¹ × 9

                                 = 47.7 × 10⁻¹¹ m

hence the radius of the third orbit will be 4.7 × 10⁻¹² m

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