Question

if the radius of the first orbit of hydrogen atom is 5.3 × 10 to the power minus 11 M then the radius of second orbit is​

Answer 1

As radius is directly proportional to n^2 ( n is orbit)

So for 2 nd orbit its 2^2 × 5.3× 10°-11

4× 5.3× 10^-11

21.2 × 10^ -11

Answer 2

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Here is your answer.....,,







$\large{ \bold{{ \: QUESTION}}} \: :-$
if the radius of the first orbit of hydrogen atom is 5.3 × 10 to the power minus 11 M then the radius of second orbit is​....?





$\large{ \bold{{ \:to \: find}}} \: :-$The Radius of the second Orbit .









$\bf{ \fbox{ \: ANSWER}}$



So,
As You can see the radius ( r ) of the orbit is directly proportional to the second orbit.






$\large{ \: radius \: of \: second \: orbit \: = {n}^{2} \times the \: radius \: of \: first \: orbit}$


$\large{ \: = {n}^{2} \times radius \: (r)}$


$\large{ \: = {2}^{2} \times 5.3 \times {10}^{ - 11}}$


$\large{ \: = 4 \times 5.3 \times {10}^{ - 11}}$


$\large{ \: = 21.2 \times {10}^{ - 11} }$








Hence..,
$\huge{ \bold{ \bf{ \fbox{ \fbox{ \color{blue}{ \underline{ \underline{ \green{ \mathfrak{ \: \: \: \: answer \: \: \: }}}}}}}}}} \:$
⬇ ⬇ ⬇ ⬇ ⬇ ⬇ ⬇ ⬇ ⬇ ⬇ ⬇ ⬇ ⬇ ⬇ ⬇ ⬇ ⬇
$\huge{ \: 21.2 \times {10}^{ - 11}}$








The Radius of the second orbit is,$\small{ \: 21.2 \times {10}^{ - 11} }$





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