Question

If the radius of the first orbit of hydrogen atom is 5.3 x 10mm, then
the radius of the second orbit is​
​

Answer 1

Answer:

Hyy dude ☺

As radius is directly proportional to n^2 ( n is orbit)

So for 2 nd orbit its 2^2 × 5.3× 10°-11

4× 5.3× 10^-11

21.2 × 10^ -11

Answer 2

\large{ \: radius \: of \: second \: orbit \: = {n}^{2} \times the \: radius \: of \: first \: orbit}

\large{ \: = {n}^{2} \times radius \: (r)}

\large{ \: = {2}^{2} \times 5.3 \times {10}^{ - 11}}

\large{ \: = 4 \times 5.3 \times {10}^{ - 11}}

\large{ \: = 21.2 \times {10}^{ - 11} }