Question

If the radius of the first shell is a0 then the radius of the third shell is [ ]
a)9a0 b)3a0
c)8a0 d)a0/8
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Answer 1

Answer:

Explanation:

Assuming its of hydrogen only

so we know that radius is 0.529 n^2/z so

for orbit number 3 its  0.529 * 9 which is 9 times the radius of first orbit

hence ans is option a)