If the radius of the gaussian surface enclosing a charge is doubled how does the electric flux through the gaussian surface changed
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Tha flux through a (closed) Gaussian surface would depend only on the net charge enclosed by the surface. The size and shape of the surface does not matter, as long as it is a closed surface. So, in this case the flux would not be change.
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Explanation:
When dipole moment vector is parallel to electric field vector.
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