if the radius of the sphere is double what is the ratio of the volume of the first sphere to that of the second sphere
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Volume of first sphere = 4×r³×π / 3 = V₁
Volume of second sphere = 4×(2r)³×π / 3 = 4×8r³×π / 3 = V₂
Ratio = V₁ / V₂
= (4×r³×π / 3) / (4×8r³×π / 3)
= 4×r³×π / 4×8r³×π
= r³ / 8r³
= 1 / 8
= 1:8
As it turns out, if the radius is increased by n (2 in this case), the volume of the sphere is increased by n³ (2³=8)
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the value is give below
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