if the radius of the sphere is doubled find the ratio of the volume of the new sphere to the original sphere
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Answered by
2
Heya
_______________________________
GOOD MORNING
=>
Volume of sphere having radius r is =
4/3(π×r³)
=>
Volume of original sphere ( V1 ) = 4/3 ) π× r³
=>
Volume of sphere when radius is doubled is ( V2) = 4/3 ( π (2r)³ )
=>
V1/ V2 ={ 4/3(πr³ ) } / (4/3) (π ×2³ × r³ )
=>
V1/V2 = 1:2³
=>
V1/V2 = 1:8
=>
V2/V1 = 8:1
So, the of new sphere to the original sphere is 8:1
_______________________________
GOOD MORNING
=>
Volume of sphere having radius r is =
4/3(π×r³)
=>
Volume of original sphere ( V1 ) = 4/3 ) π× r³
=>
Volume of sphere when radius is doubled is ( V2) = 4/3 ( π (2r)³ )
=>
V1/ V2 ={ 4/3(πr³ ) } / (4/3) (π ×2³ × r³ )
=>
V1/V2 = 1:2³
=>
V1/V2 = 1:8
=>
V2/V1 = 8:1
So, the of new sphere to the original sphere is 8:1
gauravlohani:
diagram please
Answered by
8
Answer:
Volume of sphere having radius r is =
4/3(π×r³)
=>
Volume of original sphere ( V1 ) = 4/3 ) π× r³
=>
Volume of sphere when radius is doubled is ( V2) = 4/3 ( π (2r)³ )
=>
V1/ V2 ={ 4/3(πr³ ) } / (4/3) (π ×2³ × r³ )
=>
V1/V2 = 1:2³
=>
V1/V2 = 1:8
=>
V2/V1 = 8:1
So, the of new sphere to the original sphere is 8:1
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