Question

If the radius of the sphere is increased by 100%, the
volume of the corresponding sphere is increased by?

Answer 1

Answer:

800%

Step-by-step explanation:

Let Radius of initial sphere be r. Then the volume should be

$radius = r \\ v = \frac{4}{3} {r}^{3} \pi$

Radius of sphere increased by 100%, that would be

$r + \frac{100}{100} r = r + r = 2r \\ new \: volume \\ v = \frac{4}{3} {(2r)}^{3} \pi \\ v = \frac{4 \times 8}{3} {r}^{3} \pi \\ increase \: in \: volume \\ p = \frac{ \frac{32}{3}\pi \: {r}^{3} }{ \frac{4}{3} \pi \: {r}^{3} } \times 100 \\ p = \frac{32}{4} \times 100 \\ p = 800 \: per \: cent$

Answer 2

Answer:

P- 800% Ans

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