If the radius of the sphere is increased by 100%,the volume of corresponding sphere is increased by 700% .Find true or false.Justify Your answer
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Answered by
3
Sphere volume formula is
So V is directly proportional to CUBE of radius.
so,
new radius is r + 100%r = r+r = 2r
and new Volume given is V+ 700%V = 8V
Now lets see if 2r gives volume 8V....
[tex] \frac{V_1}{V_2} = \frac{r_1^3 }{r_2^3 } V_1 = V, r_1 = r, r_2 =2r [/tex]
[tex] \frac{V}{V_2} = \frac{r^3}{(2r)^3 } = \frac{r^3}{8r^3} = \frac{1}{8} [/tex]
So V2 = 8V as expected.
hence the statement is true :)
So V is directly proportional to CUBE of radius.
so,
new radius is r + 100%r = r+r = 2r
and new Volume given is V+ 700%V = 8V
Now lets see if 2r gives volume 8V....
[tex] \frac{V_1}{V_2} = \frac{r_1^3 }{r_2^3 } V_1 = V, r_1 = r, r_2 =2r [/tex]
[tex] \frac{V}{V_2} = \frac{r^3}{(2r)^3 } = \frac{r^3}{8r^3} = \frac{1}{8} [/tex]
So V2 = 8V as expected.
hence the statement is true :)
Answered by
0
Answer: The statement is true
Step-by-step explanation:
Volume of sphere=4/3πr^3
When radius is increased by 100% then r= r+100%r
= r+r =2r
New volume = (2r) ^3
= 8r^3
So therefore when radius is increased by 100% the volume will increase by 800%
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