If the radius of the spherical base is decreased by 20%, what will be decrease in volume in percent?
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Answers
Answer:
Given:
The radius of a sphere decrease by 20%.
Concept used:
The volume of sphere =
Explanation:
Volume =
If the radius decrease 20%
r × 80% = 4r/5
New volume =
(∵ is constant in both volume so we calculated only difference of radius basis)
Initial volume = r3
New volume = 64r3/125
⇒ difference = r3 - 64r3/125 = 61r3/125
⇒ % changes =
⇒ (61/125) × 100 = 244/5 = 48.8%
∴ The percent decrease of volume is 48.8%.
Shortcut:
Given:
The radius of a sphere decrease by 20%.
Concept used:
The volume of sphere =
Explanation:
20% = 1/5
(∵ is constant in both volume so we calculated only difference of radius basis)
radius → 5 : 4
Volume → 53 : 43
Volume → 125 : 64
% decrease = {(125 - 64)/125} × 100
⇒ (61/125) × 100 = 244/5 = 48.8%
∴ The percent decrease of volume is 48.8%.
Step-by-step explanation:
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Step-by-step explanation:
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