Physics, asked by annuyadav53, 9 months ago

if the random error in the Arithmetic mean of 15 observations is alpha then the random error an error in the Arithmetic mean of 1:50 observations would be ​

Answers

Answered by Anonymous
4

Answer:

e_{2}= \frac{\alpha }{30}

Explanation :

n_{1} e_{1} = n_{2} e_{2} \\\\n = no.\  of \ observation \\\\e = error

putting the values ,

15 \alpha = 150 e_{2}

so

e_{2}= \frac{\alpha }{30}

Answered by poulamis2001
2

Explanation:

if observation is increased by 'n' times then random error decreases 1/n times

So, the ans is a/30

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