Question

if the rate constant of the first order reaction is 4.17 × 10 -3 s-1 calculate its half life period​

Answer 1

Answer:

The half-life of the given first-order reaction is $166$ s·

Explanation:

Given that,

The rate constant of the reaction $=$ $4.17\ *\ 10^{-3} s^-^1$

Also given that, the reaction follows first-order kinetics·

The half-life of a reaction is defined as, "the time required for a reactant to reduce its initial concentration to one-half"·

For a first-order reaction, the equation to calculate the half-life follows

      $t_{\frac{1}{2} }$   $=$   $\frac{0.693}{K}$

Where,

K    $=$  rate constant of the reaction

On substituting the value we get,

 ⇒  $t_{\frac{1}{2} }$   $=$  $\frac{0.693}{4.17\ *\ 10^{-3} }$

 ⇒  $t_{\frac{1}{2} }$   $=$  $166$ s

Therefore,

The half-life of the given first-order reaction is $166$ s·