If the rate of a reaction is 5 at 10°C then on increasing the temperature to 30°C new rate is ??
Explain the fact behind it .
Answers
Answered by
12
Answer:
For every 10°C rise of temperature rate constant doubles .
For 20°C rise (30° - 10° = 20°C) of temperature rate constant becomes 4 times
i.e K2 = 4K1
K2 = 4×5
Hence new rate (K2) is :-
K2 = 20°C
Hope this will help uh!!
Answered by
7
Answer:
For every 10℃ rise of temperature rate constant doubled
For 20℃ rise (30°-10°=20℃) temperature of rate constant become letins.
le.k2=4k1
k2=4×5
Hence, temperature rate (k2) is k2=20℃
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