Math, asked by abhijitdd1971, 6 months ago

If the ratio between the cost price and marked price of an article is 2:3. If the selling price of that article is Rs 1920 and the shopkeeper gave two successive discounts of 20% on the marked price. Find the loss during this transaction?

Answers

Answered by kartavyaguptasl
0

Answer:

The loss during the transaction is found to be Rs. 80.

Step-by-step explanation:

We know that the shopkeeper has provided two succesive discounts of 20% on the marked price,

Let y be the marked price. Then, the selling price will be:

SP=y-\frac{20}{100}y-(\frac{20}{100}(y-\frac{20}{100}y))

Simplifying this, we can get:

SP=y-0.2y-(0.2(y-0.2y))

SP=0.8y-(0.2(0.8y))

SP=0.8y-0.16y

or we can say:

SP=0.64y

We are given the selling price as Rs.1920, so substituting this, we get:

1920=0.64y

or we can say:

y=\frac{1920}{0.64}=3000

Thus, the marked price is found to be Rs. 3000

Now, we are given the ratio between the cost price and marked price as 2:3,

We can represent this by letting cost price as 2x and the marked price as 3x.

Equating 3x to the found marked price, we get:

MP=3x=3000

or we can say:

x=1000

By substituting x, we get the cost price as:

CP=2\times1000=2000

Thus, the cost price is found to be Rs. 2000

The loss during the transaction will be:

loss= CP-SP

loss=2000-1920

we get:

loss=80

So, there is a loss of Rs. 80 done during the transaction.

Answered by barmansuraj489
0

Concept introduction:

Ratio is a type of mathematical term which represents one upon another term which is unitless.

Given:

  • Here it is given that  marked price of an article is 2:3.
  • selling price of that article is Rs 1920
  • shopkeeper gave two successive discounts of 20‰.

To find:

We have to find the loss during this transaction.

Solution:

The loss during the transaction is found to be Rs. 80

We know that the shopkeeper has provided two succesive discounts of 20% on the marked price,

Let y be the marked price. Then, the selling price will be:

SP=y-0.2y-(0.2(y-0.2y))\\SP=0.8y-0.16y

or we can say:

SP=0.64y

We are given the selling price as Rs.1920, so substituting this, we get:

1920=0.64y

or we can say:

y=\frac{1920}{0.64} \\=3000

Thus, the marked price is found to be Rs. 3000

Now, we are given the ratio between the cost price and marked price as 2:3

We can represent this by letting cost price as 2x  and the marked price as 3x

Equating  to the found marked price, we get:

MP=3x=3000\\

or we can say:

x=1000

By substituting , we get the cost price as:

CP=2*1000\\=2000

Thus, the cost price is found to be Rs. 2000.

The loss during the transaction will be:

CP-SP\\=2000-1920\\=80

So, there is a loss of Rs. 80 done during the transaction.

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