If the ratio of 2 rupee and 5 rupee notes is 4:5 and there are total 66 rupees in the box. Then how many 2 rupee coins are there in the box??????
Answers
Answer:
here is your answer
Explanation:
Let the total number of coins be 12X.
Then,
Number of Rs.5 coins = 3X
Number of Rs.2 coins = 4X
Number of Re.1 coins = 5X
Total value of :-
Rs.5 coins = 3X * 5 = 15X
Rs.2 coins = 4X * 2 = 8X
Re.1 coins = 5X * 1 = 5X
Given, total value of all coins = 224
Therefore,
15X + 8X + 5X = 224
28X = 224
X = 8
Total number of coins = 12X = 12 * 8 = 96
Number of,
Rs.5 coins = (3/12) * 96 = 24 coins
Rs.2 coins = (4/12) * 96 = 32 coins
Re.1 coins = (5/12) * 96 = 40 coins
(Given no. of Rs.5, Rs.2, and Re.1 coins are in the ratio of 3:4:5)
Final Answer : The boy has 40 Re.1 coins.
Let's cross verify the answer once.
(24*5) + (32*2) + (40*1)
= 120 + 64 + 40
= 224 = Value given in the question.
Answer:
☆Given,
》》Total number of notes.
》》Ratio of Rs2 and Rs5 notes
☆To solve,
Number of Rs2 notes
♡Solution:
Let the number of Rs2 notes be 4x
Then, number of Rs5 notes = 5x
ACQ,
》》2×4x + 5×5x = 66
》》8x+25x=66
》》33x=66
》》x=3