India Languages, asked by rajnib98760, 5 months ago

If the ratio of 2 rupee and 5 rupee notes is 4:5 and there are total 66 rupees in the box. Then how many 2 rupee coins are there in the box??????​

Answers

Answered by Ronakbhuyan1234540
0

Answer:

here is your answer

Explanation:

Let the total number of coins be 12X.

Then,

Number of Rs.5 coins = 3X

Number of Rs.2 coins = 4X

Number of Re.1 coins = 5X

Total value of :-

Rs.5 coins = 3X * 5 = 15X

Rs.2 coins = 4X * 2 = 8X

Re.1 coins = 5X * 1 = 5X

Given, total value of all coins = 224

Therefore,

15X + 8X + 5X = 224

28X = 224

X = 8

Total number of coins = 12X = 12 * 8 = 96

Number of,

Rs.5 coins = (3/12) * 96 = 24 coins

Rs.2 coins = (4/12) * 96 = 32 coins

Re.1 coins = (5/12) * 96 = 40 coins

(Given no. of Rs.5, Rs.2, and Re.1 coins are in the ratio of 3:4:5)

Final Answer : The boy has 40 Re.1 coins.

Let's cross verify the answer once.

(24*5) + (32*2) + (40*1)

= 120 + 64 + 40

= 224 = Value given in the question.

Answered by VaibhavTheAryabhatta
5

Answer:

☆Given,

》》Total number of notes.

》》Ratio of Rs2 and Rs5 notes

☆To solve,

Number of Rs2 notes

♡Solution:

Let the number of Rs2 notes be 4x

Then, number of Rs5 notes = 5x

ACQ,

》》2×4x + 5×5x = 66

》》8x+25x=66

》》33x=66

》》x=3

☆Clearly,

♡The number of Rs2 notes = 3×4=12♡

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