if the ratio of ages A and 3:2 and there age different 24 years. then the find age of A after 3 years.
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Let suppose in present, Age of A is x and Age of B is y.
Now ratio of ages of A and B before ten years is 3:5.
So (A/B)-> Before ten years=3/5
so (x-10)/(y-10) =3/5 ………………………………………….(1)
Now the ratio of their present ages is 2:3.
So, (x/y)=2/3 …………………..(2)
From Equation (1) we get,
5x-3y=20
and from Equation (2) we get,
3x-2y=0
From these two equation we can get values of x and y.
x=40
y=60
Now Difference between their ages is = 60–40 = 20
So,final answer is 20.
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