if the ratio of ages(in years)of x and y,8 years ago is 7:6, then what will be their sum of ages after 8 years from now
Answers
Step-by-step explanation:
Given:-
the ratio of ages(in years)of x and y,8 years ago is 7:6,
To find:-
what will be their sum of ages after 8 years from now.
Solution:
the ratio of ages(in years)of x and y,8 years ago is 7:6
The ratio=7:6
Let age of x =7a
and age of y=6a
after 8 years ago their ages 7a+8+8 =7a+16 and 6a+8+8=6a+16
Sum of their ages=7a+16+6a+16=13a+32
Here we get 13a+32=13a+26+6
=>(13a+13×2)+6
=>13(a+2)+6
It means the sum of their ages is multiple of 13 which leaves remainder 6
putting a=1,2,3... we get
if a=1 ,13(1+2)+6=39+6=45
if a=2,13(2+2)+6=52+6=58
If a=3,13(3+2)+6=65+6=71
If a=4,13(4+2)+6=78+6=84
if a=5, 13(5+2)+6=91+6=97
if a=6, 13(6+2)+6=104+6=120...
Answer:-
The answer for this question is depends upon the given options
The answers may be like 45,58,71,84,97,120 years....
Answer:
the answer is 97
Step-by-step explanation:
hope this may help you