Question

if the ratio of amplitude of the two interfering light sources to is 2:1 the visibility is​

Answer 1

Answer:

Let the amplitudes be 5x and x respectively.

Let the amplitudes be 5x and x respectively.The resultant waves will have maximum amplitude when both are in phase

Let the amplitudes be 5x and x respectively.The resultant waves will have maximum amplitude when both are in phaseThey add up 5x+x=6x

Let the amplitudes be 5x and x respectively.The resultant waves will have maximum amplitude when both are in phaseThey add up 5x+x=6xDuring destructive interference the waves are out of phase

Let the amplitudes be 5x and x respectively.The resultant waves will have maximum amplitude when both are in phaseThey add up 5x+x=6xDuring destructive interference the waves are out of phaseThe resultant amplitude is x−5x=−4x

Let the amplitudes be 5x and x respectively.The resultant waves will have maximum amplitude when both are in phaseThey add up 5x+x=6xDuring destructive interference the waves are out of phaseThe resultant amplitude is x−5x=−4xMaximum intensity = (maximum amplitude)

Let the amplitudes be 5x and x respectively.The resultant waves will have maximum amplitude when both are in phaseThey add up 5x+x=6xDuring destructive interference the waves are out of phaseThe resultant amplitude is x−5x=−4xMaximum intensity = (maximum amplitude) 2=36x/2

minimum intensity = (minimum amplitude) 2=16x /2

2ratio = 16/36 = 4/9

9