Question

if the ratio of amplitude of two waves is 5 : 3 then the ratio maximum and minimum intensity is ?

Answer 1

$\huge \green{ \mathfrak{solution}}$

Given:

• The ratio of amplitude of two waves is 5:3

To find:

• The ratio of maximum and minimum intensity =?

•Let the amplitudes be

a1=5 and a2 =3.

$\implies \: \frac{a_1 }{a_2} = \frac{5}{3}$

As we know that :

$\star \: \frac{I_{max}}{I_{min}} = \frac{(a_1 +a_2)^{2} }{(a_1 - a_2) ^{2} }$

So put the values of a1 and a2 we get ,

$\star \: \frac{I_{max}}{I_{min}} = \frac{( {5 + 3)}^{2} }{( {5 - 3})^{2} } \\ \\ \star \: \frac{I_{max}}{I_{min}} = \frac{ {8}^{2} }{ {2}^{2} } = \frac{64}{4} \\ \\ \star \: \frac{I_{max}}{I_{min}} = \frac{16}{1}$

Hence the ratio is 16:1

Answer 2

Answer:

16:1

Explanation:

Amplitude ratio = 6/3

Imax/Imin=( 5+3)^2/5-3)^2

= 8×8/2×2

=64/4

=16/1