Question

If the ratio of amplitude of wave is 2 1 then the ratio of maximum and minimum intensity shall be

Answer 1

I max /l min = (a1+a2/a1-a2)^2

By using this formula

U will get the answer 9:1

Answer 2

The ratio of maximum and minimum intensity shall be 9:1

• Intensity of wave is directly proportional to square of amplitude.
• Let the amplitudes be $a_{1} and a_{2}$
• The ratio of amplitudes = 2:1

                                     $a_{1} : a_{2}$ = 2:1

• The ratio of maximum intensity to minimum intensity is given by

                   $\frac{I_{max} }{I_{min} } =( \frac{a_{1}+a_{2} }{a_{1} - a_{2} }) ^{2}$

                           = $(\frac{2+1}{2-1} )^{2}$

                           = 9/1

                           = 9:1

You can refer the attachment for derivation of relationship.