if the ratio of area of two similar triangles is equal to the square of the ratio of their corresponding sides .prove it
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from eq 3 and 4 we get
ar(ABC)/ar(PQR)=(AB/PQ)^2=(AC/PR)^2=(BC/QR)^2
ar(ABC)/ar(PQR)=(AB/PQ)^2=(AC/PR)^2=(BC/QR)^2
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