Question

If the ratio of areas of similar triangles is 16:21. what is the ratio of their corrosponding sides?



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Answer 1

Answer:

4/√21

.....................

Answer 2

Answer:

4/5

Step-by-step explanation:

Let ABC and PQR be two isosceles traingles.

=AB/AC=PQ/PR

Also, Angle A= Angle p [given]

Therefore, trangle ABC CONGRUENCE Traingle PQR by SAS simillarity.

Let AD and PS be the altitudes in the respective traingles.

We know that the ratio of areas of two similar taingles is equal to the square of their corresponding altitudes.

Area[traingle ABC]

Area[trainglePQR]

=[AD/PS]square

=16/25=[AD/PS]square

Therefore, AD/PS=4/5