Question

if the ratio of areas of similar triangles is is 16:12, what is the ratio of their corresponding sides ?1)11:8,2)11:4,3)8:11,4)4:11​

Answer 1

Answer:

Let ABC and PQR be two isosceles triangles.

⇒

AC/AB = PR/PQ

Also,∠A=∠P(given)

∴△ABC∼△PQR by SAS similarity

Let AD and PS be the altitude in the respective triangles.

We know that the ratio of areas of two similar triangles is equal to the square of their corresponding altitudes.

Area(△PQR) /Area(△ABC) = (PS/AD)²

= 16/12 =( PS/AD)²

∴ 4/3