Question

If the ratio of areas of two similar tiangles is 81:100 then what is the ratio of their corresponding sides

Answer 1

Answer:

Ratio=9:10.........

Answer 2

$\boxed{\boxed{\underline{\huge{\green{Answer}}}}}$

Using theorem:

ratio of the area of two similar traingles is equal to the square of the ratio of their corresponding sides.

ratio of two triangles given

$\pink{81:100}$

suppose the Triangles are ABC and DEF

And thier corresponding sides are AB and DE

so we have

$\mathfrak{ABC/DEF=81/100}$

$\frac{abc}{def} = \frac{ab {}^{2} }{de {}^{2} } \\ \frac{81}{100} = \frac{ab {}^{2} }{de {}^{2} } \\ \frac{ \sqrt{81} }{ \sqrt{100} } = \frac{ab}{de}$

$\boxed{\boxed{\underline{\huge{AB/DE=9/10}}}}$