If the ratio of areas of two similar triangles is l:m where l>0,m>0;what is the ratio of their corresponding sides
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The ratio of the areas of two similar triangles is equal to the square of ratio of their corresponding sides. Given: ∆ABC ~ ∆PQR To Prove: ( ())/( ()) = (/)^2 = (/)^2 = (/)^2 Construction: Draw AM ⊥ BC and PN ⊥ QR.
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