if the ratio of Cp and Cv for a gas is 1.4.The no. of atoms present in 11.2 litre of it at STP is
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Answered by
187
we know, ratio of Cp and Cv is known as atomicity.
for diatomic molecules , Cp/Cv = 1.4
hence, molecule is diatomic.
now, number of mole = volume/22.4L
given, volume = 11.2L
= 11.2L/22.4L = 0.5
now, number of molecules = mole × 6.023 × 10²³
= 0.5 × 6.023 × 10²³
= 3.0115 × 10²³
so, number of atoms = 2 × number of molecules
= 2 × 3.0115 × 10²³
= 6.023 × 10²³
for diatomic molecules , Cp/Cv = 1.4
hence, molecule is diatomic.
now, number of mole = volume/22.4L
given, volume = 11.2L
= 11.2L/22.4L = 0.5
now, number of molecules = mole × 6.023 × 10²³
= 0.5 × 6.023 × 10²³
= 3.0115 × 10²³
so, number of atoms = 2 × number of molecules
= 2 × 3.0115 × 10²³
= 6.023 × 10²³
Answered by
21
Hope it will help u
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