Question

If the ratio of diameters, lengths and Young’s modulus of steel and copper wires shown in the figure are p, q and s respectively, then the corresponding ratio of increase in their lengths would be
(a) $\frac{7q}{(5sp)}$
(b) $\frac{5q}{(7sp^{2})}$
(c) $\frac{7q}{(5sp^{2})}$
(d) $\frac{2q}{(5sp)}$

Answer 1

Hey

(a) $\frac{7q}{(5sp)}$

(b) $\frac{5q}{(7sp^{2})}$

(c) $\frac{7q}{(5sp^{2})}$

(d) $\frac{2q}{(5sp)}$

B correct

Answer 2

Explanation:

$\frac{5q}{(7sp^{2})}$ is the right answer