Question

If the ratio of enthalpy of formation of CO2 and SO2 is 4:3 and enthalpy of formation of CS, is 26 K.Cal/mol. Find the enthalpy of formation of SO2(g) on the basis of above reaction.
CS2(1) + 302(g) → CO2(g) + 2SO2(g)​

Answer 1

Answer:

C+O

2

→CO

2

,ΔH=−4x

S+O

2

→SO

2

,ΔH=−2×3x

C+2S→CS

2

,ΔH=26kcal/mol

CS

2

+3O

2

→CO

2

+2SO

2

,ΔH=−265kcal

−265=−4x−6x−(+26)⇒x=(−265+26)/10=−23.9

Enthalpy of SO

2

=−3×23.9=−71.7kcal/mol