Question

If the ratio of four angles of a quadrilateral is 3:2:4:3 find the measure of each angle

Answer 1

Answer:

Sum of interior angles of any polygons =(n-2)*180 where n is the number of sides.

∴ Sum of interior angles of quadrilateral=(4-2)*180=360

Ratios can be converted into respective proportions as such:

First angle=$360\cdot \frac{3}{3+2+4+3}=360\cdot \frac{3}{12}=90$

Second angle=$360\cdot \frac{2}{3+2+4+3}=360\cdot \frac{2}{12}=60$

Third angle=$360\cdot \frac{4}{3+2+4+3}=360\cdot \frac{4}{12}=120$

Fourth angle=$360\cdot \frac{3}{3+2+4+3}=360\cdot \frac{3}{12}=90$

Hope it helps :)

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:Take the angles as x.

So , 3x , 2x , 4x and 3x .

So we know that sum of all angles of an equilateral triangle is 360 degrees

Then,

3x + 2x + 4x + 3x = 360

12x = 360

X = 360/12

= 30

So, the angles are

3x = 3 * x = 30 * 3 = 90

2x = 2 * x = 2 * 30 = 60

4x = 4 * x = 4 * 30 = 120

3x = 3 * x = 3 * 30 = 90

I hope this helps .

Thank you.